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0.0002x^2-0.316x+127.9=8
We move all terms to the left:
0.0002x^2-0.316x+127.9-(8)=0
We add all the numbers together, and all the variables
0.0002x^2-0.316x+119.9=0
a = 0.0002; b = -0.316; c = +119.9;
Δ = b2-4ac
Δ = -0.3162-4·0.0002·119.9
Δ = 0.003936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.316)-\sqrt{0.003936}}{2*0.0002}=\frac{0.316-\sqrt{0.003936}}{0.0004} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.316)+\sqrt{0.003936}}{2*0.0002}=\frac{0.316+\sqrt{0.003936}}{0.0004} $
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